Trending · Flying Roadster Part 7: What does a 27-foot jump really take?

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// WHAT YOU WILL LEARN

8.2 m high needs about 12.7 m/s straight up and about 2.6 s in the air: v = sqrt(2gh).

// LESSON NOTES

What does a 27-foot jump really take? 📐🚗

1️⃣ THE HEIGHT: 27 ft ≈ 8.2 m — almost a 3-floor building. To get that high you need a take-off speed of about 46 km/h (28 mph) straight up. (Formula: v = √(2·g·h) ≈ 12.7 m/s.)

2️⃣ GOING UP: gravity takes 9.8 m/s off your speed every second. So the car rises for 12.7 ÷ 9.8 ≈ 1.3 seconds.

3️⃣ COMING DOWN: the fall takes the same 1.3 s. That's about 2.6 seconds in the air — if Tesla's 27 ft is right.

Up fast, down fast!

Read the voiceover (transcript)

What does a twenty-seven foot jump take?
Twenty-seven feet is eight metres. That needs forty-six kilometres an hour, straight up!
Gravity slows it every second. So it rises for one point three seconds.
And it falls for one point three more. Over two and a half seconds in the air!
Up fast, down fast!
Next: real flying cars! Follow for part eight!

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